Question

the side of square is increasing at the rate of 0.1cmper secnond the rate of increasing of perimeter w.r.t.time

Answer 1

Answer:

I did not understand you question

Answer 2

Answer:

If x cm. is the side of the square and p cm. is the perimeter.

p=4x

∴

dt

dp

=4

dt

dx

=4×0.5 (∵

dt

dx

=0.5 given)

=2

∴ The perimeter is increasing at the rate of 2 cm/sec.