the side of square is increasing at the rate of 0.1cmper secnond the rate of increasing of perimeter w.r.t.time
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If x cm. is the side of the square and p cm. is the perimeter.
p=4x
∴
dt
dp
=4
dt
dx
=4×0.5 (∵
dt
dx
=0.5 given)
=2
∴ The perimeter is increasing at the rate of 2 cm/sec.
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