the side of the cube is measured by veniar calliper whose 10 division of the verniar scale is equal to 8 devision of main scale. if the main scale reads 10mm and second devision of verniar scale coincide of main scale division then the volume of the cube is appropitae significant figure is
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hey mate your answer
Explanation:
Least count of Vernier callipers
= NumberofdivisionsinVernierscale1divisionofmainscale=101=0.1mm
Side of cube = 10mm+1×0.1mm=1.01cm
Now, density = VolumeMass=(1.01)3cm32.736g=2.66gcm^-3
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