the side of the pair of adjecent sodesbof a rectangle are in the ratio3:4.if its diagonal is 20 cm long then find the lengths of tue side hence the perimeter of the rectangle.
Answers
Answered by
83
Given that, ratio of sides = 3 : 4
So, let the sides be 3x and 4x respectively.
We know that the sides of a rectangle make an angle of 90°, thus, the diagonal acts as a hypotenuse for the triangle formed by it. Hence, by Pythagoras Theorem,
(3x)² + (4x)² = (20)²
» 9x² + 16x² = 400
» 25x² = 400
» x² = 400/25
» x² = 16
» x = √16
» x = ±4, since, length can't be negative, we will take
x = 4
So, length = 3x = 3(4) = 12 cm
breadth = 4x = 4(4) = 16 cm
So, perimeter = 2(l + b)
= 2(16 + 12)
= 2(28)
= 56 cm
Answer :- Length = 12 cm, breadth = 16 cm and perimeter = 56 cm
Answered by
88
Solution:
Given that,
Its Sides Ratio = 4 : 3
Diagonal = 25 cm
Now,
Let length and breadth be 4k and 3k respectively.
By Pythagoras theorem,
⇒ 25²= 4k² + 3k²
⇒ 625 = 16k² + 9k²
⇒ 625 = 25k²
⇒ k² = 625 / 25
⇒ k² = 25
∴ k = 5
Hence,
The length of rectangle = 4k = 20 m
And, breadth of rectangle = 3k = 15 m
Again,
Perimeter of rectangle = 2(l + b)
= 2(20+15)
= 2 × 35
= 70 m
Hence , The Required perimeter of the rectangle is 70 m.
Given that,
Its Sides Ratio = 4 : 3
Diagonal = 25 cm
Now,
Let length and breadth be 4k and 3k respectively.
By Pythagoras theorem,
⇒ 25²= 4k² + 3k²
⇒ 625 = 16k² + 9k²
⇒ 625 = 25k²
⇒ k² = 625 / 25
⇒ k² = 25
∴ k = 5
Hence,
The length of rectangle = 4k = 20 m
And, breadth of rectangle = 3k = 15 m
Again,
Perimeter of rectangle = 2(l + b)
= 2(20+15)
= 2 × 35
= 70 m
Hence , The Required perimeter of the rectangle is 70 m.
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