Question

the side of the rectangular park are in the ratio 4 : 3 if its area is 2028 square metre find the cost of fencing it at rupees 3 per metre​

Answer 1

Answer:

Solution:-

Let the length be 4x

and breadth be 3x

Area of a Rectangle = length × breadth

⇏2028 = 4x × 3x

⇏12x^2 = 2028

⇏x^2 = 2028/12

= 169

⇏x = √169

= 13

So, length = 4x = 4 × 13 = 52 m

breadth = 3x = 3 × 13 = 39 m

As fencing is done on boundary we have to find the perimeter of he field

⇏2 × ( l + b )

⇏2 × ( 52 + 39 )

⇏182 m

Cost of fencing per metre = Rs.3

Total cost = 182 × 3

= ₹546

Hope it Helps uh.....

Have a Great Day......

Answer 2

Answer:

Solution:-

Let the length be 4x

and breadth be 3x

Area of a Rectangle = length × breadth

⇏2028 = 4x × 3x

⇏12x^2 = 2028

⇏x^2 = 2028/12

= 169

⇏x = √169

= 13

So, length = 4x = 4 × 13 = 52 m

breadth = 3x = 3 × 13 = 39 m

As fencing is done on boundary we have to find the perimeter of he field

⇏2 × ( l + b )

⇏2 × ( 52 + 39 )

⇏182 m

Cost of fencing per metre = Rs.3

Total cost = 182 × 3

= ₹546

Hope it Helps uh..

Have a Great Day.