Question

The side of the square is increasing at the rate
of 0.5 cm/sec. Find the rate of increase of its area,
when the side of the square is 20 cm. long.​

Answer 1

Answer:

$\texttt{Let x= side of square A=Area of the square A= x²}$

$\texttt{Differentiating w.r.t t,}$

$\frac{dA}{dt} = 2x \frac{dx}{dt} \\ \\ now \: \frac{dx}{dt }= 0.5 \frac{cm}{sec} \\ \\ and \: x = 20cm \: (given) \\ \\ \frac{dA}{dt} = 2 \times 20 \times 0.5 \\ \\ = 20 \frac{ {cm}^{2} }{sec}$

$\texttt{Area is increasing at rate of 20 cm²/sec}$

Answer 2

Answer:

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