Math, asked by piyushkhatri, 11 months ago

the side of the square is incresing at the rate of 0.5cm/sec. find the rate of increase of its area when the side of the square is 20 cm long.​

Answers

Answered by prathamsharma2017
3

Step-by-step explanation:

area of square= l^2 l is length

we have dl/dt=0.5

we have to find da/dt at l=20cm

where a is area

a=l^2

da/dt=2ldl/dt

da/dt=2×20×0.5

da/dt=20cm^2/sec

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