the side of the square with area 4 x square - 20 X + 25
Answers
Answer:
Answer:
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♡AnSwEr♡
Explanation:
Let mass of circular disc is M and radius R.
Given, Moment of Inertia (MOI) about one of its diameter = l, ⇒ MR^2/4 = l ⇒MR^2 =4l .....1
MOI about an axis passing through the centre of the disc= MR^ 2/2
Using parallel theorem of MOI, I = I cm +mx^ 2
, Where I cm is MOI of centre of mass and x is the distance between centre of mass and axis of rotation.
MOI about an axis tangent to disc and perpendicular to its plane= MR ^2/2 +MR ^2 = 3/2 MR ^2 =6l (Using equation 1, MR ^2 =4l)
Step-by-step explanation:
Answer:
\huge{\boxed{\boxed{\underline{\rm{\pink{♡AnSwEr♡}}}}}}
♡AnSwEr♡
Explanation:
Let mass of circular disc is M and radius R.
Given, Moment of Inertia (MOI) about one of its diameter = l, ⇒ MR^2/4 = l ⇒MR^2 =4l .....1
MOI about an axis passing through the centre of the disc= MR^ 2/2
Using parallel theorem of MOI, I = I cm +mx^ 2
, Where I cm is MOI of centre of mass and x is the distance between centre of mass and axis of rotation.
MOI about an axis tangent to disc and perpendicular to its plane= MR ^2/2 +MR ^2 = 3/2 MR ^2 =6l (Using equation 1, MR ^2 =4l)