the side of the triangle are in ratio of 12:17:25 and its perimeter is 540. find the area
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2
54x = 540
X = 10
Sides = 12x , 17x , 25x
= 120,170,250
X = 10
Sides = 12x , 17x , 25x
= 120,170,250
Shobhit1231:
incomplete find the arwa
Answered by
3
let the sides be X of the triangle
therefore the sides of the triangle=12x,17x,25
perimeter of the triangle=12x+17x+25x=540
54x=540
X=540÷54=10
therefore sides are
12x=12×10=120
17x=17×10=170
25x=25×10=250
therefore the sides of the triangle=12x,17x,25
perimeter of the triangle=12x+17x+25x=540
54x=540
X=540÷54=10
therefore sides are
12x=12×10=120
17x=17×10=170
25x=25×10=250
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