Question

the side of the triangle are in the ratio of 3:4:5 and it's perimeter is 240meter find the area​

Answer 1

Answer:

2400m^2

Step-by-step explanation:

3x+4x+5x=240

12x=240

x=20

sides are 60m,80m,100m

100^2=60^2+80^2

1000=360+640

1000=1000

so this triangle is right angled triangle

area=1/2bh

=1/2 ×60×80=2400 m^2

thank you

Answer 2

3:4:5

let x be the sides of triangles

then,

3x+4x+5x=240

12x=240

x=240/12

x= 20m

AB=3x=60m

BC= 4X=80m

AC= 5X=100m

$area = \sqrt{s(s - a)(s - b)(s -c)} \\s = perimeter \div 2 \\ s = 120 \\ area = \sqrt{120(120 - 60)(120 - 80)(120 - 100)} \\ area \: = \sqrt{120 \times 60 \times 40 \times 20} \\ area = \sqrt{2 \times 60 \times 60 \times 2 \times 20 \times 20} \\ area = \sqrt{2^{2} \times 60^{2} \times 20 \ ^{2} } \\ area = 2 \times 60 \times 20 = 2400m^{2}$

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