Question

the side of triangle are 10 cm , 12 cm and 18 cm then its semi perimeter or value of are​

Answer 1

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Given :

abc is a triangle.

Side a = 10 cm

Side b = 12 cm

Side c = 14 cm

Find the semi perimeter (s) of triangle :-

s = (a+b+c)/2 unit

= (10+12+14)/2 cm

= 36/2 cm = 18 cm

Find the area of triangle by using the heron's formula :-

Area of triangle = 24√6 cm²

\begin{gathered}area = \sqrt{s(s - a)(s - b)(s - c) } \\ \\ = \sqrt{18(18 - 10)(18 - 12)(18 - 14)} \\ \\ = \sqrt{18 \times 8 \times 6 \times 4} \\ \\ = \sqrt{2 \times 3 \times 3 \times 2 \times 2 \times 2 \times 2 \times 3 \times 2 \times 2} \\ \\ = 2 \times 2 \times 2 \times 3 \times \sqrt{2 \times 3} \\ \\ = 24 \sqrt{6} \end{gathered}

Answer 2

Answer:

15 becausethe original perimter is 30 and semi then 15