the side of triangle are 12cm, 35cm, 37cm. find its area
Answers
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let side a=12cm side b=35cm and side c=37cm
∴ semi perimeter,
= (a+b+c)/2
=12+35+37/2
=84/2
=42 cm
∴area of the triangle by heron's formula,
Δ=√s(s-a)(s-b)(s-c)
Δ=√42(42-12)(42-35)(42-37 )
Δ=√42*30*7*5
Δ=√2*3*7*7*5*2*3*5
Δ=2*3*5*7
Δ=210 cm^2
∴ total area of the triangle is= 210 cm^2
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Answer:
If we denote area of the triangle by A, then the area of a triangle having sides a, b, c and s as semi-perimeter is given by;
Step-by-step explanation:
s√s(s-a) (s-b) (s-c)
a = 9 cm, b = 12 cm, c = 15 cm
Here we will calculate s,
s=a+b+c÷2
s=9+12+15/2
s=36/2
s=18cm
So the area of the triangle is
A=√18(18-9) (18-12) (18-15)
A=√18(9) (6) (3)
A=√2916
A=54cm^2