Question

The side of triangle are in ratio 25:17:12 and its perimeter in 540 cm . fimd the area of triangle


plz help Radhe krishna​

Answer 1

Answer:

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the side of triangle are in ratio 25:17:12 and its perimeter is 540cm.finf the area of the triangle.

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$let \: side \: of \: triangle \: be \: 25x \: 17x \: and12x \: respectively \\ perimeter = 540cm \: \: \: \: \: (given) \\ \underline{ \underline{atq}} \\ 25x + 17x + 12x = 540 \\ \rightarrow \: 54x = 540 \\ \rightarrow \: x = \frac{540}{54} = 10 \\ so \: side \: of \: triangle = 25x = 25 \times 10 = 250cm \\ 17x = 17 \times 10 = 170cm \\ 12x = 12 \times 10 = 120cm \\ \\ area \: of \: a \: triangle = \frac{1}{2} \times base \times hight \\ hight \: of \: triange$

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Answer 2

Step-by-step explanation:

side ratio 25:17:12

sides are 25x, 17x, 12x

perimeter of triangle =540 cm

25x+17x+12x=540

54x=540

x=540/54=10

so sides are

25x10=250

17x10=170

12x10=120

s=(a+b+c)/2=540/2=270

Now

Area of triangle =√s(s-a) (s-b) (s-c)

√(270x20x100x150)

=√(81000000)

=9000 cm^2

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