Question

The side of triangle ratio of 1:2:3 find the area?

Answer 1

Answer:

let the sides be 1x , 2x and 3x respectively

area of triangle =√s(s-a)(s-b)(s-c)

s=1x+2x+3x÷2

s=3x

therefore

area=√3x(3x-1x)(3x-2x)(3x-3x)

area=√3x*2x*1x*

area=√6x^2

area=2.44x. Ans//