The side QR of Triangle PQR is produced to a point S. If the bisectors of Angle PQR and Angle PRS meet at point T, then prove that Angle QTR = Half of Angle QPR
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Answer:
Step-by-step explanation:
Angle PRS is the exterior angle of the triangle PQ are
Angle PRS = angle PQR + angle QPR
MULTIPLY HALF ON BOTH SIDES
1/2*angle PRS = 1/2*angle PQR + angle QPR
Angle TRS = angle TQR + 1/2*angle QPR .........(1)
Angle TRS is the exterior angle of triangle TQR
Angle TRS = angle TQR + angle QTR .........(2)
(1)=(2)
angle TQR + 1/2*angle QPR = angle TQR + angle QTR
1/2*angle QPR = angle QTR
Hence proved
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