Question

The side s of a park are in the ratio 4:3.If it's area is 1728m2find the cost of fencing it at rupees 30 per metre ?

Answer 1

Answer:

hope this will help you

Answer 2

Answer:

₹5040

Step-by-step explanation:

let the length be 4x and breadth be 3x

$\implies$ $Area\:=\:l\:×\:b$

$\implies$ $1728\:=\:4x\:×3x$

$\implies$ $\Large\frac{1728}{12}$$=\:x^{2}$

$\implies$ $144\:=\:x^{2}$

$\implies$ $\sqrt{144}\:=\:x$

$\implies$ $x\:=\:12$

Now substitute x in length = 4x = 4(12) = 48m

breadth = 3x = 3(12) = 36m

$\implies$ $Perimeter\:=\:2(l\:+\:b)$

$\implies$ $P\:=\:2(48\:+\:36)$

$\implies$ $P\:=\:2(84)$

$\implies$ $P\:=\:168\:m$

Cost of fencing :

if, 1 m costs ₹30

then,168 m costs :

= $168\:×\:30$

= $\large\boxed{5,040\:rupees}$

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Mark Brainliest, if it helps :)