The sides AB and AC of AABC are produced to the points P and Q respectively, the bisectors BO and of /CBP and /BCQ meet at O then if /A = 54º, find /BOC
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Step-by-step explanation:
boc = 90 - 1/2 of 54
= 63
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answer is 54°
Step-by-step explanation:
ABCO is a rhombus an in rhombus opposite sides are equal so
<A=<O=54°
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