Question

The sides ab and ac of triangle abc are congruent bp and bq are drawn from b to make congruent angles with bc and meet ac in points p and q

Answer 1

Step-by-step explanation:

Given AB=AC

and AP=AQ

Thus

AB-AP=AC-AQ

[BP=CA ] [from figure ]

now InΔBCP & ΔBCQ

BP = CQ

∠c=∠c [common]

and BC=BC [common]

∴ΔBCP≃ΔBCQ [SAS congruency]

now

[BQ=CP] [corresponding parts of congruent triangles]