. The sides AB and AC of triangle ABC are produced to points E and D
respectively. If bisectors BO and CO of angle CBE and angle BCD meet
Respectively at O, then prove that angle BOC = 90 - 1/2 angle BAC
Answers
Answered by
0
Step-by-step explanation:
g42n1hs y7mnrbr2n6 7th 4yw
Similar questions