Question

The sides AB, BC and AC of a ∆ ABC are 3√2 cm, 2√3 cm and √30 cm. Prove that ∆ ABC is right angled triangle. Name the right angle also.
​

Answer 1

Answer:

Step-by-step explanation:

AB = 3√2 cm

BC = 2√3 cm

AC = √30 cm

2√3 < 3√2 < √30

BC < AB < AC

BC² = ( 2√3 )² = 12

AB² = ( 3√2 )² = 18

AC² = ( √30 )² = 30

12 + 18 = 30 ⇒ AB² + BC² = AC² ⇒ Δ ABC is right angled triangle.

Site AC is the longest ⇒ ∠ B is right angle.