The sides ab ,bc and ca of triangle abc touch a circle at p,qand r respectively . If pa=4cm and bp=3cm and ac =11cm then find
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AP = AR = 4cm (tangents from an external
point)
BP = BQ = 3cm (tangents from an external
point)
RC = AC - AR = 11 - 4 = 7cm
RC = QC = 7cm
BQ + QC = 3 + 7 = 10cm
BC = 10cm
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