Question

the sides ab bc ca of a triangle abc are produced in order forming exterior angles . Angles CBF ,ANGLES ACD ,AND ANGLE BAF SHOW that ANGLE ACD +ANGLE BAF SHOE THAT ANGLE ACD + ANGLE CBF =60 degree

Answer 1

Answer:

60 degree

Step-by-step explanation:

is the answer

Answer 2

Answer:

Consider ΔABC in which

∠A = 1, ∠B = 2 and ∠C = 3

Let the exterior angles of A, B and C be ∠a, ∠b and ∠c respectively.

Recall that sum of angles in a triangle is 180°

That is ∠1 + ∠2 + ∠3 = 180°

From the figure, we have:

∠1 + ∠a = 180° [Linear pair]

∠2 + ∠b = 180° [Linear pair]

∠3 + ∠c = 180° [Linear pair]

Add the above three equations, we get:

∠1 + ∠a + ∠2 + ∠b + ∠3 + ∠c = 180° + 180° + 180°

⇒ (∠1 + ∠2 + ∠3) + ∠a + ∠b + ∠c = 540°

⇒ 180°+ ∠a + ∠b + ∠c = 540°

⇒ ∠a + ∠b + ∠c = 540° – 180° = 360°

Thus sum of exterior angles of a triangle is 360°.