The sides AO and BO have been extended such that AO = OC and BO = OD. Prove that CD II AB.
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Given,
OB = OD
AO = OC
and as we can see,
angle AOB = angle DOC (vertically opposite angles)
So,
∆AOB is congruent to ∆DOC by SAS property.
So,
by cpct:-
angle BOA = angle OCD
These are alternate interior angles and hence,
CD II AB
Cheers!
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