The sides ba and dc of a quadrilateral abcd are produced ,prove that x°+y°=a°+b°
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DAB = 180-b (LP)
DCB = 180-a (LP)
(180-b) + (180-a) (x+y) ASP of a quadrilateral
360-(a+b) + (x+y) = 360 -360 = 0
x+y = a+b
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