The sides BA and DC of a quadrilateral ABCD are produced as shown below. Show that x+y=a+b.
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x+y+a+b=360° (angle sum property of quadrilateral)
x+y+x+y=360° (x+y=a+b)
2x+2y=360°
2(x+y)=360°
x+y=360/2
x+y=180°
a+b=180°
x+y=a+b
Hence,proved
x+y+x+y=360° (x+y=a+b)
2x+2y=360°
2(x+y)=360°
x+y=360/2
x+y=180°
a+b=180°
x+y=a+b
Hence,proved
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