the sides BA and DC of a quadrilateral ABCD are produced as shown in fig. prove that a+b=x +y.
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DAB = 180-b (LP)
DCB = 180 - a (LP)
180-b+180-a+x+y = 360 degree (ASP of quadrilateral)
360-(a+b)+x+y = 360
-(a+b)+x+y = 360-360 =0
Hence, x+y = a+b
DCB = 180 - a (LP)
180-b+180-a+x+y = 360 degree (ASP of quadrilateral)
360-(a+b)+x+y = 360
-(a+b)+x+y = 360-360 =0
Hence, x+y = a+b
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