The sides BC,CA and AB of triangle ABC have been produced to D , E and F respectively. find angle BAE+CBF + ACD
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himshika79:
thanks for help
Answered by
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hey
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x + y+ z = 180 (angle sum property of a triangle )
x + <3 = 180
y + <1 = 180
z +<2 = 180
by linear pair
now adding eqn (1), (2),(3)
(x + y + z )+ ( <1 + <2 + <3) = 540
<CBF + <ACD + < BAE = 540 - 180 = 360
hope helped
_____________
____
x + y+ z = 180 (angle sum property of a triangle )
x + <3 = 180
y + <1 = 180
z +<2 = 180
by linear pair
now adding eqn (1), (2),(3)
(x + y + z )+ ( <1 + <2 + <3) = 540
<CBF + <ACD + < BAE = 540 - 180 = 360
hope helped
_____________
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