Question

The sides containing the right angle of a right angled triangle are 20 cm and 21 cm respectively. what is its radius of the circumcircle of this triangle??​

Answer 1

There is a right angled triangle .

In question it is given that the lengths of sides containing the right angle are 20 cm and 21 cm .

Suppose p = 20 cm

b = 21 cm

Then h = √ ( 20^2 + 21^2 )

= √ (400 + 441)

= √ 841

= 29 cm

According to theorem the radius of a circumcircle of a right angled triangle is equals to the half of the hypotenuse of the triangle .

Hence the radius = 29 / 2 = 14.5 cm

I hope you got your answer .