The sides containing the right angle of a right angled triangle are 12cm and 16cm respectively. What is the radius of the circumcircle of this triangle?
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By use of Pythagoras' theorem, the hypotenuse is the square root of the sum of squares of the other 2 sides. So this hypotenuse is √(16^2+12^2) =√(256+144) =√400 = 20 cm. Since in a right angled triangle the hypotenuse is the diameter of its circumcircle, half its length is the radius. So the circumradius is 10 cm.
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