Question

The sides of a certain triangle are given
below. Determine which of these is
a right triangle
a = 6cm b = 8cm c = 10 cm
a = 5cm b = 8cm c =11cm​

Answer 1

Answer:

any right triangle fulfills the pythagoras theorem, which says,

(H)²=(P)²+(B)²

a. H=10cm

P=8cm

B=6cm

thus, (10)²=(8)²+(6)²

=100=64+36

100=100

therefore, part a is a right triangle.

b. H=11cm

P=8cm

B=5cm

thus, (11)²=(8)²+(5)²

=121=64+25

=121>89

therefore, part b is not a right angle triangle.

Answer 2

Answer:

In the first triangle,

By Pythgoras Theorem,

10^2 must be equal to 8^2+6^2 for it to be a right angled triangle.

We have,

64+36=100 which is square root of 10.

Thus the first triangle is right angled triangle

Now in the second triangle,

11^2 must be equal to 5^2+8^2 for it to be a right angled triangle.

We have,

11^2=121

And 25+64=89 which is not equal to 121.

Thus the second triangle is not right angled.