Question

The sides of a ∆ field are 41m ,40m,9m. Find the number of rose beds that can be prepared in the field , if each rose bed , on average needs 900 sq cm space.

Answer 1

area =
$\sqrt{s(s - a)(s - b)(s - c)}$
where
$s = \frac{a + b + c}{2} = \frac{41 + 40 + 9}{2} = \frac{90}{2} = 45$
$\sqrt{45(45 - 41)(45 - 40)(45 - 9)}$
$= \sqrt{45 \times 4 \times 5 \times 36}$
$= 6 \sqrt{9 \times 5 \times 4 \times 5}$
$= 6 \times 2 \times 5 \times 3$
$= 30 \times 6$
$180$
$180 {m}^{2} = 180 \times 10000 {cm}^{2}$
$no \: rose \: beds = \frac{180 \times 10000}{900} = \frac{180 \times 100}{9}$
$= 20 \times 100 = 2000$
2000 rose beds