Math, asked by Archanatripathi886, 11 months ago

The sides of a park are in the ratio 4:3 . if it's areas is 1728m square , find the cost of fencing it at the rate of @ rupee 3 per meter​

Answers

Answered by soumyasharma129
3

Step-by-step explanation:

read the question properly... even i messed up in between

Attachments:
Answered by irshadsyed281
12

Answer:

 \huge\bold\red{\underline{\underline{\mathfrak{Given:}}}}

Ratio of sides = 4:3

Area = 1728m²

Rate of fencing = 3Rs. Per meter

\huge\bold\pink{\underline{\underline{\mathfrak{To\:find:}}}}

Cost of fencing

\huge\bold\green{\underline{\underline{\mathfrak{Solution:}}}}

Let 'x' be the common ratio

4x × 3x = 1728

12x² = 1728

= 1728/12

= 144

x =  \sqrt{144}

X = 12

Therfore the sides are :

4 × 12 = 48m

3 × 12 = 36m

Therefore the Perimeter = 2 ( l + b)

= 2 ( 48 + 36)

= 2 (84)

= 168m

Therefore the cost of fencing = Perimeter × cost of fencing

= 168 × 3

 \huge\bold{\boxed{\boxed{Cost\:of\:fencing\:=\:504Rs.}}}}

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