Question

The sides of a pentagon are produced in order and the exterior angles so obtained measure 2x + 20°,
x-10°, 3x + 30°, 4x -15°, 5x-10°. Find the measure of x and find all the exterior angles of the Pentagon.
Pls help
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Answer 1

Step-by-step explanation:

no. of sides (n) = 5

sum of interior angle polygon = (n- 2) × 180° = (5-2) × 180° = 3 × 180° = 540°

2x + 20° + x - 10° + 3x + 30° + 4x- 15° + 5x - 10° = 540°

15x - 15° = 540°

15x = 540° + 15°

x = 555° / 15°

x = 37°

Now;

2x + 20 = 2 x 37° + 20 = 94°

x - 10° = 37° - 10° = 27°

3x + 30° = 3 x 37° + 30 = 141°

4x -15° = 4 x 37° - 15 = 133°

5x -10° = 5 x 37° -10° = 175°

Answer 2

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