the sides of a pentagon are produced in order,if the measure of exterior angles so obtained are x, 2x,3x,4x,5x find all the exterior angles
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Answer:
.sum of angles =2n-4 right angles where n is the no of sides ie 5
So 2*5-4=10-4=6 rt angles
=6*90=540°
now X+2x+3x+4x+5x+3+10+5
=540
So 15x+15+3=540
so 15(X+1)=540-3
=537
so X+1=537/15=35.8°
so X=34.8° FIRST ANSWER
Now each ext angle is
(180-int angle)
by substituting value of X in international angles we can find ext angles:
145.2
110.4
65.6
35.8
and
6°
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