the sides of a quadrilateral field taken in order are 5, 12 , 14 meters respectively, and the angle contained by the first two sides is a right angle. find its area
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Given that sides of quadrilateral are AB = 5 m, BC = 12 m, CD = 14 m and DA = 15 m AB = 5m, BC = 12m, CD = 14 m and DA = 15 m
Join AC In ∆ABC By applying Pythagoras theorem.
By using Heron’s formula,
Area of quadrilateral ABCD = area of ( ∆ABC) + Area of (∆ADC)
= 30+84 = 114 m^2
The sides of a quadrilateral taken in order are 5,12,14 and 15 meters respectively.
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