Question

The sides of a rect. are 20 cm and 15 cm. If each side of the rect. is increased by 20%, find the percent increase in the area.​

Answer 1

Answer:

✌️

Step-by-step explanation:

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Answeris

\begin{gathered}L = 20 \: cm \\ B = 15 \: cm \\ \\ Area = L \times B \\ \: \: \: \: \: \: \: \: \: \: = 20 \times 15 \: {cm}^{2} \\ \: \: \: \: \: \: \: \: \: \: = 300 \: {cm}^{2} \\ \\ New \: length = 20 + 20\% \: of \: 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 + \frac{20}{100} \times 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 24 \: cm \\ \\ New \: breadth = 15 + 20\% \: of \: 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15 + \frac{20}{100} \times 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 18 \: cm \\ \\ New \: Area = 24 \times 18 \: {cm}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 432 \: {cm}^{2} \\ \\ \% \: of \: Area \: Increased = \frac{(432 - 300)}{300} \times 100\% \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{132}{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 44 \\ \\ Ans. \: 44\%\end{gathered}

L=20cm

B=15cm

Area=L×B

=20×15cm

2

=300cm

2

Newlength=20+20%of20

=20+

100

20

×20

=24cm

Newbreadth=15+20%of15

=15+

100

20

×15

=18cm

NewArea=24×18cm

2

=432cm

2

%ofAreaIncreased=

300

(432−300)

×100%

=

3

132

=44

Ans.44%