Question

The sides of a rectangle are 20 cm and 15 cm.if each side of the rectangle is increased by 20 percentage,find the percentage increased in the area

Answer 1

L=20, B=15
Area=20×15=300
New l=20+(20%of 20)
=20+(20/100×20)
=24.
New b=15+(20%of 15)
=15+(20/100×15)
=18.
New area=24×18
=432
Difference=432-300=132
% of area increased=132/300×100
=44%
Hope it hlps:)

Answer 2

$Please \: Mark \: Me \: As \: BRAINLIEST. \\ .................................................. \\ Also \: Don't \: Forgot \: to \: Follow \: me. \\ .............. \\ As \: we \: know \: about \: Percentage. \\ So, \\ Hello \: Guys, \\ ................ \\ Answer \: is$
$L = 20 \: cm \\ B = 15 \: cm \\ \\ Area = L \times B \\ \: \: \: \: \: \: \: \: \: \: = 20 \times 15 \: {cm}^{2} \\ \: \: \: \: \: \: \: \: \: \: = 300 \: {cm}^{2} \\ \\ New \: length = 20 + 20\% \: of \: 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 + \frac{20}{100} \times 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 24 \: cm \\ \\ New \: breadth = 15 + 20\% \: of \: 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15 + \frac{20}{100} \times 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 18 \: cm \\ \\ New \: Area = 24 \times 18 \: {cm}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 432 \: {cm}^{2} \\ \\ \% \: of \: Area \: Increased = \frac{(432 - 300)}{300} \times 100\% \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{132}{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 44 \\ \\ Ans. \: 44\%$