Question

the sides of a rectangle are 20 cm and 15 cm . if each side of the rectangle is increased by 20% , find the percentage increases in the area if you are intelligent give answer

Answer 1

$\large{\boxed{\bold{Answer:}}}$

Length = 20

Breadth = 15

Area = l × b

= 20 × 15 = 300m²

$l = 20 + 20\% \times 20 = 20 + 4 = 24 \\ \\ b = 15 + 20\% \times 15 = 15 + 3 = 18 \\ \\ area = 24 \times 18 = 432$

Increased area will be 432-300= 132

$percentage\:of\:increased \: area = \frac{132}{432} \times 100 = 30.5\%$

The total increase would be 30.5%

$\large{\boxed{\bold{Hope\:it\:helps\:you!}}}$

Answer 2

$Please \: Mark \: Me \: As \: BRAINLIEST. \\ .................................................. \\ Also \: Don't \: Forgot \: to \: Follow \: me. \\ .............. \\ As \: we \: know \: about \: Percentage. \\ So, \\ Hello \: Guys, \\ ................ \\ Answer \: is$
$L = 20 \: cm \\ B = 15 \: cm \\ \\ Area = L \times B \\ \: \: \: \: \: \: \: \: \: \: = 20 \times 15 \: {cm}^{2} \\ \: \: \: \: \: \: \: \: \: \: = 300 \: {cm}^{2} \\ \\ New \: length = 20 + 20\% \: of \: 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 + \frac{20}{100} \times 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 24 \: cm \\ \\ New \: breadth = 15 + 20\% \: of \: 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15 + \frac{20}{100} \times 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 18 \: cm \\ \\ New \: Area = 24 \times 18 \: {cm}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 432 \: {cm}^{2} \\ \\ \% \: of \: Area \: Increased = \frac{(432 - 300)}{300} \times 100\% \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{132}{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 44 \\ \\ Ans. \: 44\%$