Question

the sides of a rectangle are 33 centimeter the sides of another rectangle are 11 centimeter and 6 centimeter what is the ratio of their areas can you find other pairs of rectangles with such a relation

Answer 1

Answer:

Let the side of square field be= 60 m

The length of the rectangular field be l= 80 m and breadth be b m.

According to the question

Perimeter of the square = perimeter of rectangle

4×a = 2 (l+b)

4×60 = 2 (80+b)

240 = 160+2b

2b = 80

b= 40

Area of square= 60×60= 3600m

2

Area of rectangle = 80× 40= 3200 m

2

So, area of the square is greater than the area of rectangle

Step-by-step explanation:

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