Question

The sides of a rectangle are 33 centimetres. The sides of another rectangle are 11 centimetres and 6 centimetres. What is the ratio of their perimeters? And the ratio of their areas? Can you find other pairs of rectangles with such a relation?​

Answer 1

Answer:

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Step-by-step explanation:

Solution:

Let the side of square field be a=60 m

Let the length of the rectangular field be l=80 m and breadth be b m.

According to the question

perimeter of square = Perimeter of rectangle

4×a=2(l+b)

⇒4×60=2(80+b)

⇒240=160+2b

⇒2b=80

⇒b=40

Area of square =60×60=3600m

2

Area of rectangle=80×40=3200m

2

So, the area of the square is greater than the area of the rectangle.