Question

The sides of a rectangle are 3a² +6b and 4a² + b. find it's perimeter.​

Answer 1

Heya!  ✌️

Lets do it mate:

Perimeter = 2(a+b)

= 2 ( 3a^2 + 6b + 4a^2 + b)

= 2 ( 12a^2 + 7b )

= 14a^2 + 14b

perimeter of the rectangle is 14a^2 + 14b

Hope it helps ❣️