the sides of a rectangle are 3cm and 4cm . what is the length of both the diagonals?
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The length of both the diagonals is 5cm
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the diagonals formed in a rectangle are the HYPOTENUSE of the sides of the rectangle 3 cm ,4 cm
We know that, 3, 4, 5 is a Pythagorean triplet, by this we get
there are two diagonal, so 2(5) = 10 cm
OR
let x be the length of the diagonal
by pythagoras theorem,
x² = 3² + 4²
x = √(9+16) = √25 = 5
there are such two diagonals , so 2x = 2(5) = 10 cm
Hope you understand
any doubts, comment ;)(
We know that, 3, 4, 5 is a Pythagorean triplet, by this we get
there are two diagonal, so 2(5) = 10 cm
OR
let x be the length of the diagonal
by pythagoras theorem,
x² = 3² + 4²
x = √(9+16) = √25 = 5
there are such two diagonals , so 2x = 2(5) = 10 cm
Hope you understand
any doubts, comment ;)(
Better be aware
;))
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