Question

the sides of a rectangle are -4x+6y+3z and 12x-4y+9z.find its perimeter

Answer 1

Answer:

PERIMETER = 16'+4y+24z

Step-by-step explanation:

PERIMETER = 2(-4x+6y+3z+12x-4y+9z)

PERIMETER = 2(8x+2y+12z)

PERIMETER = 16x+4y+24z

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Answer 2

$\rm{Perimeter\:of\:Rectangle=2\times[Length+Breadth]}$

$\longrightarrow\rm{Perimeter\:of\:Rectangle=2\times[(12x-4y+9z)+(-4x+6y+3z)]}$

$\longrightarrow\rm{Perimeter\:of\:Rectangle=2\times[12x-4y+9z-4x+6y+3z]}$

$\longrightarrow\rm{Perimeter\:of\:Rectangle=2\times[12x-4x-4y+6y+9z+3z]}$

$\longrightarrow\rm{Perimeter\:of\:Rectangle=2\times[8x+2y+12z]}$

$\longrightarrow\rm{Perimeter\:of\:Rectangle=16x+4y+24z}$