Question

The sides of a rectangle are in the ratio 4:3 and it's area is 972sq.m.What is the perimeter of the rectangle

Answer 1

Step-by-step explanation:

let,ratio 4:3 be 4x and 3x respectively.

then,

length=4x and breadth=3x

now,

area of rectangle=length×breadth

972m^2=4x×3×

972m^2=12x^2

972m^2÷12=x^2

81m^2=x^2

square root of 81m^2=x

9m=x

x=9m

again

perimeter of rectangle=2(l+b)

=2(4x+3x)

=2(4×9m+3×9m)

=2(36m+27m)

=2×63

=126

Answer 2

✬ Perimeter = 126 m ✬

Step-by-step explanation:

Given:

• Sides of rectangle are in ratio 4 : 3.
• Area of rectangle is 972 m².

To Find:

• What is the perimeter of the rectangle?

Solution: Let x be the common in given ratio. Therefore,

• Length = 4x
• Breadth = 3x

★ Area of rectangle = Length x Breadth★

But the area of rectangle is 972 m² given.

$\implies{\rm }$ 972 = (4x $\times$ 3x]

$\implies{\rm }$ 972 = 12x²

$\implies{\rm }$ 972/12 = x²

$\implies{\rm }$ 81 = x²

$\implies{\rm }$ √9 $\times$ 9 = x

$\implies{\rm }$ 9 m = x

∴ Length of rectangle = 4x = 4(9) = 36 m.

Breadth of rectangle = 3x = 3(9) = 27 m.

Now, We have to find the perimeter

★ Perimeter of rectangle = 2(Length + Breadth) ★

$\implies{\rm }$ Perimeter = 2 ( 36 + 27 )

$\implies{\rm }$ Perimeter = 2 $\times$ 63

$\implies{\rm }$ Perimeter = 126 m

Hence, The perimeter of rectangle is 126 m.