The sides of a rectanglular park are in the ratio 4:3.if the area is 1728m find the cost of fencing it at the rate if rupees 2.50
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Heya !!!
Here is your answer,
Given : -
The sides of a rectangular park are in the ratio 4:3
Area of the park = 1728m
Let the sides of rectangle be
length = 4x m
breadth = 3x m
Area of the rectangular park = 1728
=> length×breadth = 1728
=> 4x × 3x = 1728
=> 12x² = 1728
=> x² = 1728/12
=> x² = 144
=> x = √144
=> x = 12
Now,
length = 4x = 4×12 = 48 m
breadth = 3x = 3×12 = 36 m
As fencing is done in perimeter.
So,
Perimeter of rectangular park = 2(length+breadth)
= 2(48+36)
= 2×84
= 168 m
If cost of fencing 1 m = ₹ 2.50
Then cost of fencing the rectangular park of perimeter 168 = 168×2.50 = ₹420
Hope it helps.
Here is your answer,
Given : -
The sides of a rectangular park are in the ratio 4:3
Area of the park = 1728m
Let the sides of rectangle be
length = 4x m
breadth = 3x m
Area of the rectangular park = 1728
=> length×breadth = 1728
=> 4x × 3x = 1728
=> 12x² = 1728
=> x² = 1728/12
=> x² = 144
=> x = √144
=> x = 12
Now,
length = 4x = 4×12 = 48 m
breadth = 3x = 3×12 = 36 m
As fencing is done in perimeter.
So,
Perimeter of rectangular park = 2(length+breadth)
= 2(48+36)
= 2×84
= 168 m
If cost of fencing 1 m = ₹ 2.50
Then cost of fencing the rectangular park of perimeter 168 = 168×2.50 = ₹420
Hope it helps.
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