Math, asked by saisucheth, 1 year ago

The sides of a rectanglular park are in the ratio 4:3.if the area is 1728m find the cost of fencing it at the rate if rupees 2.50

Answers

Answered by Preetigupta1
1
I hope it will be help you.....!!
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Answered by MiniDoraemon
2
Heya !!!

Here is your answer,

Given : -
The sides of a rectangular park are in the ratio 4:3
Area of the park = 1728m

Let the sides of rectangle be
length = 4x m
breadth = 3x m

Area of the rectangular park = 1728

=> length×breadth = 1728

=> 4x × 3x = 1728

=> 12x² = 1728

=> x² = 1728/12

=> x² = 144

=> x = √144

=> x = 12

Now,
length = 4x = 4×12 = 48 m
breadth = 3x = 3×12 = 36 m

As fencing is done in perimeter.

So,
Perimeter of rectangular park = 2(length+breadth)

= 2(48+36)

= 2×84

= 168 m

If cost of fencing 1 m = ₹ 2.50

Then cost of fencing the rectangular park of perimeter 168 = 168×2.50 = ₹420



Hope it helps.
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