Question

The sides of a rectangular field are as 3 : 4 and the
area of the field is 1452 sq. metres. Find its sides
(length and breadth).​

Answer 1

Let the length of sides of the rectangle be a and b. According to the question ab=1452m2−(i)ab=1452m2−(i) and a:b=4:3a:b=4:3 or ab=43ab=43

or, a=43b−(ii)a=43b−(ii)

Substituting the value of a into (i)

43b2=1452m243b2=1452m2

b2=3∗14524m2b2=3∗14524m2

b2=1089m2b2=1089m2

b=1089−−−−√m=33mb=1089m=33m

Substituting the value of b into (ii),

a=43∗33=44ma=43∗33=44m

So, the side lengths of the field are 33 m and 44 m. Since generally the term length is used for the longer side, the length of the field is 44 m.

Answer 2

This was an easy question!

Here is the solution :

2( 3x + 4x ) = 1452

14x = 1452

x = 13

Length = 52 m

Breadth = 39 m