Question

The sides of a rectangular field of 1350 sq.m area in the ratio 3:2.what is its perimeter.

Answer 1

We have,
Area of rectangular field = 1350 m².
Sides of the field are in the ratio of 3:2.
So,
Let the common factor of the sides be x.
So length of field = 3x and breadth = 2x.
As we know the area of the rectangle is l*b (where l=length and b=breadth).


Therefore,
1350=3x*2x
1350=6x²
6x²=1350
x²=1350/6
x²=225
x=√225
x=15

We have found the common factor for the sides.

Hence,
l = 3x = 3*15 = 45 and b = 2x = 2*15 = 30.
So,
we know that perimeter of rectangle is 2(l+b)
Therefore,
Perimeter (p) = 2(l+b)
p = 2(45+30)
p = 90+60
p=150

Hence, perimeter of rectangular field is 150m.