Question

The sides of a rectangular field of 726 sq. m are in the ratio of 3:2. find tje sides?

Answer 1

Let the sides of a rectangle which are in ratio be 3x and 2x respectively.
Now,
Area of Rectangle = 726
=> 3x*2x = 726
=> 6x^2 = 726
=> x^2 = 121
=> x = 11 m
Hence, the sides of the rectangle is 33 m and 22 m...... Ans....

Hope it helps u.....

Answer 2

Given:

The sides of a rectangular field of 726 sq. m are in the ratio of 3:2.

To find:

The sides.

Solution:

As we know that the area of a rectangle having length 'l' and breadth 'b' is given by using the formula:

$area = l \times b$

Now,

as given, we have

The ratio of sides of a rectangular field = 3:2

Let x be the highest common factor between the two sides.

So,

The two sides are 3x and 2x.

Area of rectangular field = 726 sq. m

So,

$3x \times 2x = 726$

$6 {x}^{2} = 726$

${x}^{2} = 121$

$x = 11$

(as the side cannot be negative, so x = -11 is neglected)

So,

The two sides are

$3(11) = 33 \: m$

$2(11) = 22 \: m$

Hence, the two sides of a rectangular field are 33m and 22m.