Question

the sides of a rectangular Park are in the ratio 3:2 if its area is 1536 m square find the cost of fencing it @ rupees 23. 50 per metre

Answer 1

Let the length and width be 3a and 2a

=> Area = 1536

=> 3a × 2a = 1536

=> 6a^2 = 1536

=> a^2 = 256

=> a = 16 m

Length = 48 m

Width = 32 m

Perimeter = 2( Length + Width)

= 2 × 80

= 160 m

Cost of fencing = Perimeter × Rate

= Rs 160 × 23.50

= Rs 3760

Answer 2

HI FRIEND

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HERE IS YOUR ANSWER :-

GIVEN :

SIDES OF A RECTANGULAR PARK ARE IN THE RATIO 3 : 2.

LET :

LENGTH = 3X

BREADTH = 2X

GIVEN :

AREA OF A RECTANGULAR PARK =
1536 m^2

AREA OF A RECTANGULAR PARK = LENGTH × BREADTH

3X × 2X = 1536

6X^2 = 1536

X^2 = 1536/6

X^2 = 256

X = √256

X = 16 m

THEREFORE :

LENGTH = 3X

LENGTH = 3 × 16

LENGTH = 48 m

THEREFORE :

BREADTH = 2X

BREADTH = 2 × 16

BREADTH = 32 m

THEREFORE :

PERIMETER OF A RECTANGULAR PARK = 2 (LENGTH + BREADTH)

= 2 (48 + 32)

= 2 (80 m)

= 160 m

GIVEN :

COST OF FENCING A RECTANGULAR PARK FOR 1 METRE = Rs. 23.50

COST OF FENCING A RECTANGULAR PARK FOR 160 METRE = 23.50 × 160

= RS. 3760

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HOPE IT HELPS

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