the sides of a rectangular park are in the ratio 4:3 .if it area is 2028 sq .m find the cost
of fencing it at Rs 3 per meter
Answers
Answered by
5
Answer:
Rs 546
Step-by-step explanation:
Let, length (l) = 4x, breadth (b) = 3x
Area = l * b
or, 2028 = 4x * 3x
or, 12 x^2 = 2028
or, x^2 = 169
∴ x = 13 m
l= 52 m
b = 39 m
Perimeter = 2* (52+39)m = 182 m
So, Cost = Rs 3 * 182
= Rs 546
mrsvaibhav:
thanks broo
Answered by
1
Hey mate!!!
Here is the answer to your query...
Cost of fencing 1 sq.m area = Rs 3
Cost of fencing 2028 sq.m area = 2028 × 3
= 6084 rs
Let us assume the measures of length and breadth be 4x and 3x respectively
Area of rectangle = 2028
l × b = 2028
4x × 3x = 2028
12x^2 = 2028
x^2 = 2028/12
x^2 = 169
x = \sqrt{169}
x = 13
Then,
Length of the rectangular park = 4x = 4(13)
= 52m
Breadth of the rectangular park = 3x = 3(13)
=39m
Hope it helps!!!
Please mark it as brainliest...
Regards
Here is the answer to your query...
Cost of fencing 1 sq.m area = Rs 3
Cost of fencing 2028 sq.m area = 2028 × 3
= 6084 rs
Let us assume the measures of length and breadth be 4x and 3x respectively
Area of rectangle = 2028
l × b = 2028
4x × 3x = 2028
12x^2 = 2028
x^2 = 2028/12
x^2 = 169
x = \sqrt{169}
x = 13
Then,
Length of the rectangular park = 4x = 4(13)
= 52m
Breadth of the rectangular park = 3x = 3(13)
=39m
Hope it helps!!!
Please mark it as brainliest...
Regards
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