the sides of a rectangular park are in the ratio 4:3.if its area is 1728m² , find the cost of fencing it at
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Let ,The Common Ratio between the two sides be x.
Therefore,length will be = 4x, and breadth will be = 3x
We know that ,
Area = l × b
1728 = 4x × 3x [Because Area 1728 m2]
⇒ 12x2 = 1728
⇒ x2 = 1728/12
⇒ x2 = 144 = (12)2
∴ x = 12
∴ Length = 4x = 4 × 12 = 48 m
Breadth = 3x = 3 × 12 = 36 m
(i) Now, perimeter = 2(l + b)
= 2 (48 + 36) m
= 2 × 84 = 168 m
(ii) Rate of fencing = ₹ 40 per metre
Total cost =168 × 40 = ₹ 672
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